If overrightarrow{R} is the resultant vector | vedclass

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(B) According to the triangle law of vector addition,the magnitude of the resultant vector $\overrightarrow{R} = \overrightarrow{A} + \overrightarrow{

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less than or equal to

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(B) According to the triangle law of vector addition,the magnitude of the resultant vector $\overrightarrow{R} = \overrightarrow{A} + \overrightarrow{B}$ is given by $|\overrightarrow{R}| = \sqrt{|\overrightarrow{A}|^2 + |\overrightarrow{B}|^2 + 2|\overrightarrow{A}| |\overrightarrow{B}| \cos 	heta}$,where $	heta$ is the angle between the vectors.Since the maximum value of $\cos 	heta$ is $1$ (when $	heta = 0^\circ$),the maximum value of $|\overrightarrow{R}|$ is $|\overrightarrow{A}| + |\overrightarrow{B}|$.For any other angle,$|\overrightarrow{R}|$ will be less than $|\overrightarrow{A}| + |\overrightarrow{B}|$.Therefore,the relationship is $|\overrightarrow{R}| \leq |\overrightarrow{A}| + |\overrightarrow{B}|$.

If $\overrightarrow{R}$ is the resultant vector of two vectors $\overrightarrow{A}$ and $\overrightarrow{B}$,then $|\overrightarrow{R}|$ is . . . . . . $|\overrightarrow{A}| + |\overrightarrow{B}|$.

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